What is (\partial)/(\partial x)(cos(2x-3y^2)) ?

The answer to (\partial)/(\partial x)(cos(2x-3y^2)) is -sin(2x-3y^2)*2

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(\partial)/(\partial x)(cos(2x-3y^2))

\frac{\partial}{\partial x} (cos (2 x - 3 y^{2}))

- sin (2 x - 3 y^{2}) \cdot 2

Solution steps

\frac{\partial}{\partial x} (cos (2 x - 3 y^{2}))

Treat

y

as a constant

Apply the chain rule:

- sin (2 x - 3 y^{2}) \frac{\partial}{\partial x} (2 x - 3 y^{2})

= - sin (2 x - 3 y^{2}) \frac{\partial}{\partial x} (2 x - 3 y^{2})

\frac{\partial}{\partial x} (2 x - 3 y^{2}) = 2

= - sin (2 x - 3 y^{2}) \cdot 2

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What is (\partial)/(\partial x)(cos(2x-3y^2)) ?
The answer to (\partial)/(\partial x)(cos(2x-3y^2)) is -sin(2x-3y^2)*2