What is taylor-(3x-4)^3,3 ?

The answer to taylor-(3x-4)^3,3 is -125-225(x-3)-135(x-3)^2-27(x-3)^3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

taylor-(3x-4)^3,3

taylor

- (3 x - 4)^{3}, 3

- 125 - 225 (x - 3) - 135 (x - 3)^{2} - 27 (x - 3)^{3}

Solution steps

Apply the Taylor Formula

= - 125 + \frac{\frac{d}{d x} ( - ( 3 x - 4 ) ^{3} ) ( 3 )}{1 !} (x - 3) + \frac{\frac{d ^{2}}{d x ^{2}} ( - ( 3 x - 4 ) ^{3} ) ( 3 )}{2 !} (x - 3)^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( - ( 3 x - 4 ) ^{3} ) ( 3 )}{3 !} (x - 3)^{3} + \dots

Evaluate Derivatives

= - 125 + \frac{- 225}{1 !} (x - 3) + \frac{- 270}{2 !} (x - 3)^{2} + \frac{- 162}{3 !} (x - 3)^{3} + \frac{0}{4 !} (x - 3)^{4} + \frac{0}{5 !} (x - 3)^{5} + \frac{0}{6 !} (x - 3)^{6} + \frac{0}{7 !} (x - 3)^{7} + \frac{0}{8 !} (x - 3)^{8} + \frac{0}{9 !} (x - 3)^{9} + \frac{0}{10 !} (x - 3)^{10}

Refine

= - 125 - 225 (x - 3) - 135 (x - 3)^{2} - 27 (x - 3)^{3}

\int_{0}^{\frac{3 π}{2}} 5 ∣ sin (x) ∣ d x

\frac{x ^{2}}{2 + x}

\int_{- 1}^{64} \frac{1}{x ^{\frac{1}{3}}} d x

n = 1 \sum \infty \frac{2}{3 ^{n}}

x \to 2 lim (3 + 2 x + x^{2})

What is taylor-(3x-4)^3,3 ?
The answer to taylor-(3x-4)^3,3 is -125-225(x-3)-135(x-3)^2-27(x-3)^3