What is the derivative of (y^{3/2})/3-y^{1/2} ?

The derivative of (y^{3/2})/3-y^{1/2} is (y^{1/2})/2-1/(2y^{1/2)}

What is the first derivative of (y^{3/2})/3-y^{1/2} ?

The first derivative of (y^{3/2})/3-y^{1/2} is (y^{1/2})/2-1/(2y^{1/2)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

\frac{y ^{\frac{3}{2}}}{3} - y^{\frac{1}{2}}

\frac{y ^{\frac{1}{2}}}{2} - \frac{1}{2 y ^{\frac{1}{2}}}

Solution steps

\frac{d}{d y} (\frac{y ^{\frac{3}{2}}}{3} - y^{\frac{1}{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d y} (\frac{y ^{\frac{3}{2}}}{3}) - \frac{d}{d y} (y^{\frac{1}{2}})

\frac{d}{d y} (\frac{y ^{\frac{3}{2}}}{3}) = \frac{y ^{\frac{1}{2}}}{2}

\frac{d}{d y} (y^{\frac{1}{2}}) = \frac{1}{2 y ^{\frac{1}{2}}}

= \frac{y ^{\frac{1}{2}}}{2} - \frac{1}{2 y ^{\frac{1}{2}}}

f (x) = ln (sinh (x^{2}))

\frac{d}{d x} (e^{2 x} - x)

(\frac{1}{x ^{4}})^{^{'}}

f (x) = arccos (e^{2 x})

\frac{\partial}{\partial x} (4 - x^{4} + 2 x^{2} - y^{2})

What is the derivative of (y^{3/2})/3-y^{1/2} ?
The derivative of (y^{3/2})/3-y^{1/2} is (y^{1/2})/2-1/(2y^{1/2)}
What is the first derivative of (y^{3/2})/3-y^{1/2} ?
The first derivative of (y^{3/2})/3-y^{1/2} is (y^{1/2})/2-1/(2y^{1/2)}