What is the derivative of 9e^x+4/(\sqrt[3]{x}) ?

The derivative of 9e^x+4/(\sqrt[3]{x}) is 9e^x-4/(3x^{4/3)}

What is the first derivative of 9e^x+4/(\sqrt[3]{x}) ?

The first derivative of 9e^x+4/(\sqrt[3]{x}) is 9e^x-4/(3x^{4/3)}

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9 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

Solution steps

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} (9 e^{x}) = 9 e^{x}

= 9 e^{x} - \frac{4}{3 x ^{\frac{4}{3}}}

x \to 6 lim (\frac{x - 3}{x - 1})

\frac{d ^{3}}{d x ^{3}} ((x - 1) ln (x))

\int x (x^{3} - 1) d x

\int \frac{1}{x ^{5}} d x

\int \frac{1 + x}{4 + 2 x + x ^{2}} d x

What is the derivative of 9e^x+4/(\sqrt[3]{x}) ?
The derivative of 9e^x+4/(\sqrt[3]{x}) is 9e^x-4/(3x^{4/3)}
What is the first derivative of 9e^x+4/(\sqrt[3]{x}) ?
The first derivative of 9e^x+4/(\sqrt[3]{x}) is 9e^x-4/(3x^{4/3)}