What is the integral from 0 to 8 of sqrt(x+1) ?

The integral from 0 to 8 of sqrt(x+1) is 52/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 8 of sqrt(x+1)

\int_{0}^{8} x + 1 d x

\frac{52}{3}

Decimal Notation

17.33333 \dots

Solution steps

\int_{0}^{8} x + 1 d x

Apply u-substitution

: \int_{1}^{9} u d u

= \int_{1}^{9} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{1}^{9}

= [\frac{2}{3} u^{\frac{3}{2}}]_{1}^{9}

Compute the boundaries:

\frac{52}{3}

= \frac{52}{3}

\int e^{20 t} 6 sin (2 t) d t

\frac{d x}{d t} + 0.1 x = 10

\int \frac{6 s ^{2} - 2}{s ^{3}} d s

\frac{1}{2 x + 5}

2 x^{2} - 3 x + 5

What is the integral from 0 to 8 of sqrt(x+1) ?
The integral from 0 to 8 of sqrt(x+1) is 52/3