What is the first derivative of 3x^2-1 ?

The first derivative of 3x^2-1 is 6x

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derivative of 3x^2-1

\frac{d}{d x} (3 x^{2} - 1)

6 x

Solution steps

\frac{d}{d x} (3 x^{2} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (1)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (1) = 0

= 6 x - 0

Simplify

= 6 x

\int (x^{2} + 1)^{- 1} d x

f (x) = 4^{x} - x^{2} + 3 ln (x)

\frac{40 t ^{2}}{t ^{2} + 150}

x \to 0 + lim (\frac{3}{x} - \frac{2}{ln ( x )})