What is the derivative of (16)/((x^2y^2)) ?

The derivative of (16)/((x^2y^2)) is -(32)/(x^3y^2)

What is the first derivative of (16)/((x^2y^2)) ?

The first derivative of (16)/((x^2y^2)) is -(32)/(x^3y^2)

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derivative of

\frac{16}{( x ^{2} y ^{2} )}

- \frac{32}{x ^{3} y ^{2}}

Solution steps

\frac{d}{d x} (\frac{16}{x ^{2} y ^{2}})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{16}{y ^{2}} \frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{16}{y ^{2}} \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{16}{y ^{2}} (- 2 x^{- 2 - 1})

Simplify

\frac{16}{y ^{2}} (- 2 x^{- 2 - 1}) : - \frac{32}{x ^{3} y ^{2}}

= - \frac{32}{x ^{3} y ^{2}}

\frac{d}{d y} (ln (x - 2 y))

\frac{d}{d r} (π r^{2})

x sin^{2} (2 x)

\frac{d}{d x} (7^{x^{4} + 2})

\frac{d}{d x} (ln (ln (9 x)))

What is the derivative of (16)/((x^2y^2)) ?
The derivative of (16)/((x^2y^2)) is -(32)/(x^3y^2)
What is the first derivative of (16)/((x^2y^2)) ?
The first derivative of (16)/((x^2y^2)) is -(32)/(x^3y^2)