What is the derivative of (2x-1^3(3x+2)^4) ?

The derivative of (2x-1^3(3x+2)^4) is 6(2x-1)^2(3x+2)^4+12(3x+2)^3(2x-1)^3

What is the first derivative of (2x-1^3(3x+2)^4) ?

The first derivative of (2x-1^3(3x+2)^4) is 6(2x-1)^2(3x+2)^4+12(3x+2)^3(2x-1)^3

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\frac{d}{d x} ((2 x - 1)^{3} (3 x + 2)^{4})

6 (2 x - 1)^{2} (3 x + 2)^{4} + 12 (3 x + 2)^{3} (2 x - 1)^{3}

Solution steps

\frac{d}{d x} ((2 x - 1)^{3} (3 x + 2)^{4})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = (2 x - 1)^{3}, g = (3 x + 2)^{4}

= \frac{d}{d x} ((2 x - 1)^{3}) (3 x + 2)^{4} + \frac{d}{d x} ((3 x + 2)^{4}) (2 x - 1)^{3}

\frac{d}{d x} ((2 x - 1)^{3}) = 6 (2 x - 1)^{2}

\frac{d}{d x} ((3 x + 2)^{4}) = 12 (3 x + 2)^{3}

= 6 (2 x - 1)^{2} (3 x + 2)^{4} + 12 (3 x + 2)^{3} (2 x - 1)^{3}

\frac{d y}{d x} = tan (x)

n = 0 \sum \infty x^{(1 + n)}

\int_{- 1}^{0} - 5 x (3 x^{2} - 2)^{3} d x

\frac{d P}{d t} = P (1 0^{- 1} - 1 0^{- 7} P), P (0) = 7000

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What is the derivative of (2x-1^3(3x+2)^4) ?
The derivative of (2x-1^3(3x+2)^4) is 6(2x-1)^2(3x+2)^4+12(3x+2)^3(2x-1)^3
What is the first derivative of (2x-1^3(3x+2)^4) ?
The first derivative of (2x-1^3(3x+2)^4) is 6(2x-1)^2(3x+2)^4+12(3x+2)^3(2x-1)^3