What is the derivative of (x-1/4) ?

The derivative of (x-1/4) is 1/4

What is the first derivative of (x-1/4) ?

The first derivative of (x-1/4) is 1/4

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\frac{d}{d x} (\frac{x - 1}{4})

\frac{1}{4}

Solution steps

\frac{d}{d x} (\frac{x - 1}{4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{4} \frac{d}{d x} (x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{4} (\frac{d x}{d x} - \frac{d}{d x} (1))

\frac{d x}{d x} = 1

\frac{d}{d x} (1) = 0

= \frac{1}{4} (1 - 0)

Simplify

= \frac{1}{4}

\frac{d}{d x} (8 arcsin (x^{3}))

\int 7 + x^{2} d x

x^{^{''}} - 0.1 x^{^{'}} + x = 0

y \frac{d y}{d x} = x + 2

\int (\frac{x}{2})^{2} d x

What is the derivative of (x-1/4) ?
The derivative of (x-1/4) is 1/4
What is the first derivative of (x-1/4) ?
The first derivative of (x-1/4) is 1/4