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Popular >

integral from 1 to 4 of x^2+2x-5

Solution

\int_{1}^{4} x^{2} + 2 x - 5 d x

Solution

21

Solution steps

\int_{1}^{4} x^{2} + 2 x - 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} x^{2} d x + \int_{1}^{4} 2 x d x - \int_{1}^{4} 5 d x

\int_{1}^{4} x^{2} d x = 21

\int_{1}^{4} 2 x d x = 15

\int_{1}^{4} 5 d x = 15

= 21 + 15 - 15

Simplify

= 21

Popular Examples

integral of (x-5)

\int (x - 5) d x

area y=-3x+12,y=2x^2-11x+12 area

y = - 3 x + 12, y = 2 x^{2} - 11 x + 12

integral of (sin(2s))/(cos(2s))

\int \frac{sin ( 2 s )}{cos ( 2 s )} d s

integral of 120x

\int 120 x d x

sum from n=1 to infinity of (n+1)/n

n = 1 \sum \infty \frac{n + 1}{n}

Frequently Asked Questions (FAQ)

What is the integral from 1 to 4 of x^2+2x-5 ?
The integral from 1 to 4 of x^2+2x-5 is 21