What is the solution for (dy)/(dx)=-((2y^2))/(x^2) ?

The solution for (dy)/(dx)=-((2y^2))/(x^2) is y=-x/(2+c_{1)x}

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(dy)/(dx)=-((2y^2))/(x^2)

\frac{d y}{d x} = - \frac{( 2 y ^{2} )}{x ^{2}}

y = - \frac{x}{2 + c _{1} x}

Solution steps

\frac{d y}{d x} = - \frac{( 2 y ^{2} )}{x ^{2}}

Solve separable ODE:

y = - \frac{x}{2 + c _{1} x}

y = - \frac{x}{2 + c _{1} x}

a x^{^{''}} + b x = 0

\frac{d}{d x} (e^{t a n h (2 x)})

y^{^{'}} - e^{2 x + y} = 0

\int 1 - cos (6 x) d x

t \to 1 lim (\frac{\frac{1}{t} - 1}{t - 1})

What is the solution for (dy)/(dx)=-((2y^2))/(x^2) ?
The solution for (dy)/(dx)=-((2y^2))/(x^2) is y=-x/(2+c_{1)x}