What is the derivative of (x^3/3+c) ?

The derivative of (x^3/3+c) is x^2

What is the first derivative of (x^3/3+c) ?

The first derivative of (x^3/3+c) is x^2

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\frac{d}{d x} (\frac{x ^{3}}{3} + c)

x^{2}

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{3} + c)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{3}}{3}) + \frac{d c}{d x}

\frac{d}{d x} (\frac{x ^{3}}{3}) = x^{2}

\frac{d c}{d x} = 0

= x^{2} + 0

Simplify

= x^{2}

x \to 5 lim (\frac{x ^{3} + 8}{x + 2})

\frac{d}{d x} (x - \frac{1}{1 + x})

\int \frac{( x + 4 )}{x ^{2} + 2 x + 5} d x

\frac{s}{( s ^{2} + 25 ) ( s - 1 )}

x (x + 1) \frac{d y}{d x} + x y = 1, y (e) = 1

What is the derivative of (x^3/3+c) ?
The derivative of (x^3/3+c) is x^2
What is the first derivative of (x^3/3+c) ?
The first derivative of (x^3/3+c) is x^2