What is the tangent of 7x-4sqrt(x) ?

The tangent of 7x-4sqrt(x) is y=(7-2/(sqrt(a_{0))})x-2sqrt(a_{0)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of 7x-4sqrt(x)

tangent of

7 x - 4 x

y = (7 - \frac{2}{a _{0}}) x - 2 a_{0}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 7 a_{0} - 4 a_{0})

Find the slope of

y = 7 x - 4 x : \frac{d y}{d x} = 7 - \frac{2}{x}

Compute the slope of

y = 7 x - 4 x

x = a_{0} : m = 7 - \frac{2}{a _{0}}

Find the line with slope m=

7 - \frac{2}{a _{0}}

and passing through

(a_{0}, 7 a_{0} - 4 a_{0}) : y = (7 - \frac{2}{a _{0}}) x - 2 a_{0}

y = (7 - \frac{2}{a _{0}}) x - 2 a_{0}

y^{^{'}} - y^{\frac{5}{3}} = 0

\int \frac{x}{x - 20} d x

\frac{1}{1 + \frac{1}{1 + x}}

\frac{1}{3} t^{3} - 4 t^{2} + 16 t + 7

x \to 0 lim (lo g_{2} (x))

What is the tangent of 7x-4sqrt(x) ?
The tangent of 7x-4sqrt(x) is y=(7-2/(sqrt(a_{0))})x-2sqrt(a_{0)}