What is the derivative of x^2y^4 ?

The derivative of x^2y^4 is 2xy^4+4y^3(dy)/(dx)x^2

What is the first derivative of x^2y^4 ?

The first derivative of x^2y^4 is 2xy^4+4y^3(dy)/(dx)x^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (x^{2} y^{4})

2 x y^{4} + 4 y^{3} \frac{d y}{d x} x^{2}

Solution steps

\frac{d}{d x} (x^{2} y^{4})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2}, g = y^{4}

= \frac{d}{d x} (x^{2}) y^{4} + \frac{d}{d x} (y^{4}) x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (y^{4}) = 4 y^{3} \frac{d y}{d x}

= 2 x y^{4} + 4 y^{3} \frac{d y}{d x} x^{2}

x \to 2 lim (x^{2} - 5)

\int 3 x^{2} + cos (x) d x

x \to 0 lim (\frac{1 - e ^{- x}}{x})

\frac{d}{d x} (\frac{x ^{2}}{x ^{3}})

e^{x} (x^{2} + 1) (x + 4)

What is the derivative of x^2y^4 ?
The derivative of x^2y^4 is 2xy^4+4y^3(dy)/(dx)x^2
What is the first derivative of x^2y^4 ?
The first derivative of x^2y^4 is 2xy^4+4y^3(dy)/(dx)x^2