What is the derivative of log_{2}(x-1-2) ?

The derivative of log_{2}(x-1-2) is 1/(ln(2)(x-1))

What is the first derivative of log_{2}(x-1-2) ?

The first derivative of log_{2}(x-1-2) is 1/(ln(2)(x-1))

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\frac{d}{d x} (lo g_{2} (x - 1) - 2)

\frac{1}{ln ( 2 ) ( x - 1 )}

Solution steps

\frac{d}{d x} (lo g_{2} (x - 1) - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (lo g_{2} (x - 1)) - \frac{d}{d x} (2)

\frac{d}{d x} (lo g_{2} (x - 1)) = \frac{1}{ln ( 2 ) ( x - 1 )}

\frac{d}{d x} (2) = 0

= \frac{1}{ln ( 2 ) ( x - 1 )} - 0

Simplify

= \frac{1}{ln ( 2 ) ( x - 1 )}

y = x^{2} e^{x} - 2 x e^{x} + 6 e^{x}

f (x) = 16 x, at x = 16

(2 x^{- 2} + 3)^{- 3}

\int \frac{1}{1 0 ^{5} x - x ^{2}} d x

\int 4 x^{\frac{1}{3}} + 2 x^{- \frac{1}{3}} d x

What is the derivative of log_{2}(x-1-2) ?
The derivative of log_{2}(x-1-2) is 1/(ln(2)(x-1))
What is the first derivative of log_{2}(x-1-2) ?
The first derivative of log_{2}(x-1-2) is 1/(ln(2)(x-1))