What is the integral of 1/(3\sqrt[3]{x^5)} ?

The integral of 1/(3\sqrt[3]{x^5)} is -1/(2x^{2/3)}+C

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integral of 1/(3\sqrt[3]{x^5)}

- \frac{1}{2 x ^{\frac{2}{3}}} + C

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

assuming

x \geq 0

= \frac{1}{3} \cdot \int \frac{1}{x ^{\frac{5}{3}}} d x

Apply the Power Rule

: - \frac{3}{2 x ^{\frac{2}{3}}}

= \frac{1}{3} (- \frac{3}{2 x ^{\frac{2}{3}}})

Simplify

\frac{1}{3} (- \frac{3}{2 x ^{\frac{2}{3}}}) : - \frac{1}{2 x ^{\frac{2}{3}}}

= - \frac{1}{2 x ^{\frac{2}{3}}}

Add a constant to the solution

= - \frac{1}{2 x ^{\frac{2}{3}}} + C

\int_{t - 1}^{2} - t + 2 d t

f (x) = (2 x + 3)^{3}

\frac{d}{d x} (1 + 3 x)

\int_{1}^{4} t^{4} ln (3 t) d t

\int (x^{2} - 2 x + 1) e^{2 x} d x

What is the integral of 1/(3\sqrt[3]{x^5)} ?
The integral of 1/(3\sqrt[3]{x^5)} is -1/(2x^{2/3)}+C