What is (\partial)/(\partial y)(y^2+x) ?

The answer to (\partial)/(\partial y)(y^2+x) is 2y

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(\partial)/(\partial y)(y^2+x)

\frac{\partial}{\partial y} (y^{2} + x)

2 y

Solution steps

\frac{\partial}{\partial y} (y^{2} + x)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (y^{2}) + \frac{\partial}{\partial y} (x)

\frac{\partial}{\partial y} (y^{2}) = 2 y

\frac{\partial}{\partial y} (x) = 0

= 2 y + 0

Simplify

= 2 y

\frac{1}{s} - \frac{s}{s ^{2} + 1}

\int \frac{1}{2 3 - x x + 1} d x

\frac{d}{d x} (ln (x^{2} e^{x}))

n = 0 \sum \infty \frac{1}{( n ^{3} - n )}

y^{^{'}} + 8 x - 1 y = x^{8}, y (1) = 9

What is (\partial)/(\partial y)(y^2+x) ?
The answer to (\partial)/(\partial y)(y^2+x) is 2y