What is (\partial)/(\partial x)(2sin(3x+2y)) ?

The answer to (\partial)/(\partial x)(2sin(3x+2y)) is 6cos(3x+2y)

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(\partial)/(\partial x)(2sin(3x+2y))

\frac{\partial}{\partial x} (2 sin (3 x + 2 y))

6 cos (3 x + 2 y)

Solution steps

\frac{\partial}{\partial x} (2 sin (3 x + 2 y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{\partial}{\partial x} (sin (3 x + 2 y))

Apply the chain rule:

cos (3 x + 2 y) \frac{\partial}{\partial x} (3 x + 2 y)

= cos (3 x + 2 y) \frac{\partial}{\partial x} (3 x + 2 y)

\frac{\partial}{\partial x} (3 x + 2 y) = 3

= 2 cos (3 x + 2 y) \cdot 3

Simplify

= 6 cos (3 x + 2 y)

\int \frac{y + 1}{y} d y

\frac{d}{d x} (e^{x} cos (x^{2}))

y \to - 1 lim (- y^{5} - 3 y^{4})

f (x) = e^{2 x}, (0, 1)

n = 1 \sum \infty (- 1)^{n} n^{- 1}

What is (\partial)/(\partial x)(2sin(3x+2y)) ?
The answer to (\partial)/(\partial x)(2sin(3x+2y)) is 6cos(3x+2y)