What is (\partial)/(\partial z)(e^x+yz) ?

The answer to (\partial)/(\partial z)(e^x+yz) is y

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(\partial)/(\partial z)(e^x+yz)

\frac{\partial}{\partial z} (e^{x} + yz)

y

Solution steps

\frac{\partial}{\partial z} (e^{x} + yz)

Treat

x, y

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial z} (e^{x}) + \frac{\partial}{\partial z} (yz)

\frac{\partial}{\partial z} (e^{x}) = 0

\frac{\partial}{\partial z} (yz) = y

= 0 + y

Simplify

= y

f (x)

x \to 6 + lim (\frac{x}{36 - x ^{2}})

\frac{d}{d x} (2 x arcsin (x))

x \to 2 lim ([x])

\frac{d}{d x} (\frac{2 x ^{3} + x ^{2} - 2 x}{x ^{4} - 2 x ^{2} - 4})

What is (\partial)/(\partial z)(e^x+yz) ?
The answer to (\partial)/(\partial z)(e^x+yz) is y