What is the derivative of f(t)=5t-8t^2 ?

The derivative of f(t)=5t-8t^2 is 5-16t

What is the first derivative of f(t)=5t-8t^2 ?

The first derivative of f(t)=5t-8t^2 is 5-16t

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derivative of

f (t) = 5 t - 8 t^{2}

5 - 16 t

Solution steps

\frac{d}{d t} (5 t - 8 t^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (5 t) - \frac{d}{d t} (8 t^{2})

\frac{d}{d t} (5 t) = 5

\frac{d}{d t} (8 t^{2}) = 16 t

= 5 - 16 t

\frac{\partial}{\partial y} (- x y^{2} z + 4 x y)

\frac{\partial}{\partial x} (sin (x + y) + (x + y))

\int \frac{3}{x ^{3} + x} d x

\int_{0}^{2} t e^{2 t} d t

\frac{\partial}{\partial x} (x^{2} e^{3 x y})

What is the derivative of f(t)=5t-8t^2 ?
The derivative of f(t)=5t-8t^2 is 5-16t
What is the first derivative of f(t)=5t-8t^2 ?
The first derivative of f(t)=5t-8t^2 is 5-16t