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Popular >

y^'=e^{2x}(1+y^2)

Solution

y^{^{'}} = e^{2 x} (1 + y^{2})

Solution

y = tan (\frac{1}{2} e^{2 x} + c_{1})

Solution steps

y^{'} (x) = e^{2 x} (1 + y^{2})

Solve separable ODE:

y = tan (\frac{1}{2} e^{2 x} + c_{1})

y = tan (\frac{1}{2} e^{2 x} + c_{1})

Popular Examples

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\int y^{2} - 2 x d x

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\int x e^{- 8 x} d x

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limit as x approaches-infinity of x+1

x \to - \infty lim (x + 1)

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{2x}(1+y^2) ?
The solution for y^'=e^{2x}(1+y^2) is y=tan(1/2 e^{2x}+c_{1})