What is the derivative of f(x)=x^2-2x+1 ?

The derivative of f(x)=x^2-2x+1 is 2x-2

What is the first derivative of f(x)=x^2-2x+1 ?

The first derivative of f(x)=x^2-2x+1 is 2x-2

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derivative of

f (x) = x^{2} - 2 x + 1

2 x - 2

Solution steps

\frac{d}{d x} (x^{2} - 2 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (2 x) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= 2 x - 2 + 0

Simplify

= 2 x - 2

\frac{d}{d x} (e^{- 0.4 x})

6 t - \frac{2}{t}

\frac{d}{d x} (\frac{1}{3} x^{3} - \frac{1}{2} x^{2} - 6 x)

\frac{3 s + 17}{s ^{2} + s + 1}

What is the derivative of f(x)=x^2-2x+1 ?
The derivative of f(x)=x^2-2x+1 is 2x-2
What is the first derivative of f(x)=x^2-2x+1 ?
The first derivative of f(x)=x^2-2x+1 is 2x-2