What is the tangent of f(x)=x^{-2},\at x=-2 ?

The tangent of f(x)=x^{-2},\at x=-2 is y= 1/4 x+3/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=x^{-2},\at x=-2

tangent of

f (x) = x^{- 2}, at x = - 2

y = \frac{1}{4} x + \frac{3}{4}

Solution steps

Find the tangent point:

(- 2, \frac{1}{4})

Find the slope of

f (x) = x^{- 2} : \frac{df ( x )}{d x} = - \frac{2}{x ^{3}}

Compute the slope of

f (x) = x^{- 2}

x = - 2 : m = \frac{1}{4}

Find the line with slope m=

\frac{1}{4}

and passing through

(- 2, \frac{1}{4}) : y = \frac{1}{4} x + \frac{3}{4}

y = \frac{1}{4} x + \frac{3}{4}

\frac{\partial}{\partial p} (\frac{( p + q )}{p + r})

x \to 0 lim (\frac{sin ( 4 x )}{cos ( 5 x )})

\frac{d}{d x} (- 3 x^{3} + 2 x^{2} + 5 x - 2)

x \to 0 lim ((x^{2}) sin (\frac{1}{x}))

\int \frac{x ^{2} + x + 1}{x ^{3} + 2 x ^{2}} d x

What is the tangent of f(x)=x^{-2},\at x=-2 ?
The tangent of f(x)=x^{-2},\at x=-2 is y= 1/4 x+3/4