What is area 7e^x,7xe^{x^2},1,7e ?

The answer to area 7e^x,7xe^{x^2},1,7e is -7(e^{7e}-e)+(7(e^{49e^2}-e))/2

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area 7e^x,7xe^{x^2},1,7e

area

7 e^{x}, 7 x e^{x^{2}}, 1, 7 e

- 7 (e^{7 e} - e) + \frac{7 ( e ^{49 e^{2}} - e )}{2}

Decimal Notation

6.11443 E 157

Solution steps

Apply the area formula:

\int_{1}^{7 e} 7 e^{x} - 7 x e^{x^{2}} d x

Solve

\int_{1}^{7 e} 7 e^{x} - 7 x e^{x^{2}} d x : - 7 (e^{7 e} - e) + \frac{7 ( e ^{49 e^{2}} - e )}{2}

The area is:

= - 7 (e^{7 e} - e) + \frac{7 ( e ^{49 e^{2}} - e )}{2}

f (x) = \frac{x}{( 1 + x ^{2} )}, at x = 2

\frac{d}{d x} (\frac{3}{x ^{6}} - \frac{1}{x ^{4}} + 5)

f (x) = (3 x^{2} + 2) (8 x^{3} - 3)

\frac{d y}{d x} = 5 y x

What is area 7e^x,7xe^{x^2},1,7e ?
The answer to area 7e^x,7xe^{x^2},1,7e is -7(e^{7e}-e)+(7(e^{49e^2}-e))/2