What is the limit as x approaches 4 of \sqrt[3]{x} ?

The limit as x approaches 4 of \sqrt[3]{x} is cube root of 4

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limit as x approaches 4 of \sqrt[3]{x}

Decimal Notation

1.58740 \dots

Solution steps

Plug in the value

x = 4

x \to 5 + lim (\frac{x + 2}{5 - x})

\int 2 x \cdot sin (x) \cdot e^{x} d x

\int \frac{1}{x 5 + x ^{2}} d x

\frac{d}{d x} (5 x sin (4 π) x)

\int 3 x^{2} y^{- 2} + 2 x y^{- 1} d x

What is the limit as x approaches 4 of \sqrt[3]{x} ?
The limit as x approaches 4 of \sqrt[3]{x} is cube root of 4