What is the derivative of f(x)=x^2-5,c=3 ?

The derivative of f(x)=x^2-5,c=3 is 2x

What is the first derivative of f(x)=x^2-5,c=3 ?

The first derivative of f(x)=x^2-5,c=3 is 2x

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derivative of

f (x) = x^{2} - 5, c = 3

2 x

Solution steps

\frac{d}{d x} (x^{2} - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (5)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (5) = 0

= 2 x - 0

Simplify

= 2 x

\int_{- 2}^{3} \frac{24}{x ^{4}} d x

x y^{^{'}} - 3 y^{2} = 0, y (e) = 1

\int - e^{2 x} sin (e^{x}) d x

ln (x + 7)

\frac{d}{d x} (\frac{x}{3} - 1)

What is the derivative of f(x)=x^2-5,c=3 ?
The derivative of f(x)=x^2-5,c=3 is 2x
What is the first derivative of f(x)=x^2-5,c=3 ?
The first derivative of f(x)=x^2-5,c=3 is 2x