What is the tangent of y=(6x)/(x^2+1),(0,0) ?

The tangent of y=(6x)/(x^2+1),(0,0) is y=6x

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tangent of y=(6x)/(x^2+1),(0,0)

tangent of

y = \frac{6 x}{x ^{2} + 1}, (0, 0)

y = 6 x

Solution steps

Find the slope of

y = \frac{6 x}{x ^{2} + 1} : \frac{d y}{d x} = \frac{6 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

Compute the slope of

y = \frac{6 x}{x ^{2} + 1}

(0, 0) : m = 6

Find the line with slope m=

6

and passing through

(0, 0) : y = 6 x

y = 6 x

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What is the tangent of y=(6x)/(x^2+1),(0,0) ?
The tangent of y=(6x)/(x^2+1),(0,0) is y=6x