What is area y= 1/x ,y= 1/3 ,1,3 ?

The answer to area y= 1/x ,y= 1/3 ,1,3 is ln(3)-2/3

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area y= 1/x ,y= 1/3 ,1,3

area

y = \frac{1}{x}, y = \frac{1}{3}, 1, 3

ln (3) - \frac{2}{3}

Decimal Notation

0.43194 \dots

Solution steps

Apply the area formula:

\int_{1}^{3} \frac{1}{x} - \frac{1}{3} d x

Solve

\int_{1}^{3} \frac{1}{x} - \frac{1}{3} d x : ln (3) - \frac{2}{3}

The area is:

= ln (3) - \frac{2}{3}

\int \frac{1}{x ^{2} + 2 x - 3} d x

\frac{d}{d x} (\frac{x ^{6}}{6})

y = cot^{2} (sin (θ))

\frac{d}{d x} (\frac{x ^{2}}{2 x + 1})

3 y^{^{''}} + 13 y^{^{'}} + 4 y = 0

What is area y= 1/x ,y= 1/3 ,1,3 ?
The answer to area y= 1/x ,y= 1/3 ,1,3 is ln(3)-2/3