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Popular >

2y^{''}+32y=0

Solution

2 y^{^{''}} + 32 y = 0

Solution

y = c_{1} cos (4 t) + c_{2} sin (4 t)

Solution steps

2 y^{''} (t) + 32 y = 0

Solve linear ODE:

y = c_{1} cos (4 t) + c_{2} sin (4 t)

y = c_{1} cos (4 t) + c_{2} sin (4 t)

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\int 5 x^{2} e^{6 x} d x

integral of sec(t)

\int sec (t) d t

Frequently Asked Questions (FAQ)

What is the solution for 2y^{''}+32y=0 ?
The solution for 2y^{''}+32y=0 is y=c_{1}cos(4t)+c_{2}sin(4t)