What is the derivative of 4e^{-3x} ?

The derivative of 4e^{-3x} is -12e^{-3x}

What is the first derivative of 4e^{-3x} ?

The first derivative of 4e^{-3x} is -12e^{-3x}

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\frac{d}{d x} (4 e^{- 3 x})

- 12 e^{- 3 x}

Solution steps

\frac{d}{d x} (4 e^{- 3 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (e^{- 3 x})

Apply the chain rule:

e^{- 3 x} \frac{d}{d x} (- 3 x)

= e^{- 3 x} \frac{d}{d x} (- 3 x)

\frac{d}{d x} (- 3 x) = - 3

= 4 e^{- 3 x} (- 3)

Simplify

= - 12 e^{- 3 x}

\frac{d}{d x} (- cos (2 x) - 2 sin (2 x) (1 - x))

x \frac{d y}{d x} + 2 y = x^{2}

x \to 0 lim (\frac{x}{sin ^{2} ( x )})

\frac{d}{d x} (\frac{x}{8 x + 3})

\frac{d y}{d x} = (3 - 2 y) \cdot x^{3}

What is the derivative of 4e^{-3x} ?
The derivative of 4e^{-3x} is -12e^{-3x}
What is the first derivative of 4e^{-3x} ?
The first derivative of 4e^{-3x} is -12e^{-3x}