What is the derivative of sqrt(6t^2-t) ?

The derivative of sqrt(6t^2-t) is (12t-1)/(2sqrt(6t^2-t))

What is the first derivative of sqrt(6t^2-t) ?

The first derivative of sqrt(6t^2-t) is (12t-1)/(2sqrt(6t^2-t))

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derivative of

6 t^{2} - t

\frac{12 t - 1}{2 6 t ^{2} - t}

Solution steps

\frac{d}{d t} (6 t^{2} - t)

Apply the chain rule:

\frac{1}{2 6 t ^{2} - t} \frac{d}{d t} (6 t^{2} - t)

= \frac{1}{2 6 t ^{2} - t} \frac{d}{d t} (6 t^{2} - t)

\frac{d}{d t} (6 t^{2} - t) = 12 t - 1

= \frac{1}{2 6 t ^{2} - t} (12 t - 1)

Simplify

\frac{1}{2 6 t ^{2} - t} (12 t - 1) : \frac{12 t - 1}{2 6 t ^{2} - t}

= \frac{12 t - 1}{2 6 t ^{2} - t}

f (x) = x^{2} tan (x)

\int \frac{1}{x ^{2} + x - 1} d x

\int_{1}^{4} \frac{4}{x ^{2} + 4 x + 4} d x

x \to 0 lim (- 2)

\frac{d}{d x} (8 cos (3 x))

What is the derivative of sqrt(6t^2-t) ?
The derivative of sqrt(6t^2-t) is (12t-1)/(2sqrt(6t^2-t))
What is the first derivative of sqrt(6t^2-t) ?
The first derivative of sqrt(6t^2-t) is (12t-1)/(2sqrt(6t^2-t))