What is the integral from 0 to pi/2 of 3cos(x) ?

The integral from 0 to pi/2 of 3cos(x) is 3

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integral from 0 to pi/2 of 3cos(x)

\int_{0}^{\frac{π}{2}} 3 cos (x) d x

3

Solution steps

\int_{0}^{\frac{π}{2}} 3 cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{\frac{π}{2}} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= 3 [sin (x)]_{0}^{\frac{π}{2}}

Compute the boundaries:

1

= 3 \cdot 1

Simplify

= 3

f (x) = (3 x^{3} + 2 x) (x - 2) (x + 4)

\int \frac{1}{( 4 x ^{2} - 25 ) ^{\frac{3}{2}}} d x

\int - 4 x^{2} - 12 x - 5 d x

x \to 0 + lim (\frac{2}{x})

\int \frac{1}{x ^{π}} d x

What is the integral from 0 to pi/2 of 3cos(x) ?
The integral from 0 to pi/2 of 3cos(x) is 3