What is the derivative of f(x)=322560(2x+5) ?

The derivative of f(x)=322560(2x+5) is 645120

What is the first derivative of f(x)=322560(2x+5) ?

The first derivative of f(x)=322560(2x+5) is 645120

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derivative of

f (x) = 322560 (2 x + 5)

645120

Solution steps

\frac{d}{d x} (322560 (2 x + 5))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 322560 \frac{d}{d x} (2 x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= 322560 (\frac{d}{d x} (2 x) + \frac{d}{d x} (5))

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (5) = 0

= 322560 (2 + 0)

Simplify

= 645120

\frac{d y}{d x} = sin (5 x), y (0) = 2

\frac{d ^{3}}{d x ^{3}} (x + 1)

n = 0 \sum \infty \frac{n !}{5 ^{n}}

(4, - 7), (2, - 1)

\frac{d}{d x} (8 y sin (x))

What is the derivative of f(x)=322560(2x+5) ?
The derivative of f(x)=322560(2x+5) is 645120
What is the first derivative of f(x)=322560(2x+5) ?
The first derivative of f(x)=322560(2x+5) is 645120