What is the integral from 0 to pi of-cos(x) ?

The integral from 0 to pi of-cos(x) is 0

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integral from 0 to pi of-cos(x)

\int_{0}^{π} - cos (x) d x

0

Solution steps

\int_{0}^{π} - cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{0}^{π} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= - [sin (x)]_{0}^{π}

Compute the boundaries:

0

= - 0

Simplify

= 0

cos (x) \frac{d y}{d x} + y sin (x) = 1

x \to 0 lim (lo g_{\frac{1}{2}} (x))

\frac{x ^{3}}{x + 1}

\int 18 e^{x} d x

\int_{0}^{64} \frac{5}{x ^{\frac{2}{3}}} d x

What is the integral from 0 to pi of-cos(x) ?
The integral from 0 to pi of-cos(x) is 0