What is the integral of (x^2)/(x^{3+1)} ?

The integral of (x^2)/(x^{3+1)} is -1/x+C

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integral of (x^2)/(x^{3+1)}

\int \frac{x ^{2}}{x ^{3 + 1}} d x

- \frac{1}{x} + C

Solution steps

\int \frac{x ^{2}}{x ^{3 + 1}} d x

Simplify

\frac{x ^{2}}{x ^{3 + 1}} : \frac{1}{x ^{2}}

= \int \frac{1}{x ^{2}} d x

Apply the Power Rule

: - \frac{1}{x}

= - \frac{1}{x}

Add a constant to the solution

= - \frac{1}{x} + C

\frac{1}{x}

\frac{d}{d x} (ln (cosh (5 x)))

\frac{d}{d x} (\frac{4 + x}{x e ^{x}})

\int \frac{1}{3} e^{t} d t

f (x) = ln (\frac{5 x + 3}{5 x - 3})

What is the integral of (x^2)/(x^{3+1)} ?
The integral of (x^2)/(x^{3+1)} is -1/x+C