What is the tangent of y=xsqrt(x),(1,1) ?

The tangent of y=xsqrt(x),(1,1) is y= 3/2 x-1/2

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tangent of y=xsqrt(x),(1,1)

tangent of

y = x x, (1, 1)

y = \frac{3}{2} x - \frac{1}{2}

Solution steps

Find the slope of

y = x x : \frac{d y}{d x} = \frac{3 x}{2}

Compute the slope of

y = x x

(1, 1) : m = \frac{3}{2}

Find the line with slope m=

\frac{3}{2}

and passing through

(1, 1) : y = \frac{3}{2} x - \frac{1}{2}

y = \frac{3}{2} x - \frac{1}{2}

\frac{d}{d x} (\frac{x}{sin ( x )})

\frac{\partial}{\partial x} (x^{\frac{1}{4}})

x \to 1 lim (2 x + 3)

\int cos (2 x) cos (6 x) d x

\int_{- r}^{r} 4 (r^{2} - x^{2}) d x

What is the tangent of y=xsqrt(x),(1,1) ?
The tangent of y=xsqrt(x),(1,1) is y= 3/2 x-1/2