What is the derivative of (sin(2x)/(tan(x))) ?

The derivative of (sin(2x)/(tan(x))) is -2sin(2x)

What is the first derivative of (sin(2x)/(tan(x))) ?

The first derivative of (sin(2x)/(tan(x))) is -2sin(2x)

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\frac{d}{d x} (\frac{sin ( 2 x )}{tan ( x )})

- 2 sin (2 x)

Solution steps

\frac{d}{d x} (\frac{sin ( 2 x )}{tan ( x )})

Simplify

\frac{sin ( 2 x )}{tan ( x )} : 2 cos^{2} (x)

= \frac{d}{d x} (2 cos^{2} (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (cos^{2} (x))

Apply the chain rule:

2 cos (x) \frac{d}{d x} (cos (x))

= 2 cos (x) \frac{d}{d x} (cos (x))

\frac{d}{d x} (cos (x)) = - sin (x)

= 2 \cdot 2 cos (x) (- sin (x))

Simplify

2 \cdot 2 cos (x) (- sin (x)) : - 2 sin (2 x)

= - 2 sin (2 x)

\frac{1}{( x + 2 )}

\int_{2}^{3} t^{3} d t

\frac{d}{d x} (x + \frac{64}{x})

\int \frac{3}{x ^{2} ( x ^{2} + 25 )} d x

What is the derivative of (sin(2x)/(tan(x))) ?
The derivative of (sin(2x)/(tan(x))) is -2sin(2x)
What is the first derivative of (sin(2x)/(tan(x))) ?
The first derivative of (sin(2x)/(tan(x))) is -2sin(2x)