What is the integral from 2 to 3 of t^3 ?

The integral from 2 to 3 of t^3 is 65/4

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integral from 2 to 3 of t^3

\int_{2}^{3} t^{3} d t

\frac{65}{4}

Decimal Notation

16.25

Solution steps

\int_{2}^{3} t^{3} d t

Apply the Power Rule

: [\frac{t ^{4}}{4}]_{2}^{3}

= [\frac{t ^{4}}{4}]_{2}^{3}

Compute the boundaries:

\frac{65}{4}

= \frac{65}{4}

\frac{d}{d x} (x + \frac{64}{x})

\int \frac{3}{x ^{2} ( x ^{2} + 25 )} d x

\int \frac{1}{36 + x ^{2}} d x

\frac{27}{x ^{2} + 9}

What is the integral from 2 to 3 of t^3 ?
The integral from 2 to 3 of t^3 is 65/4