What is area (8cos(pix)),(8x^2-2),[-0.5,0.5] ?

The answer to area (8cos(pix)),(8x^2-2),[-0.5,0.5] is 6.42629…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area (8cos(pix)),(8x^2-2),[-0.5,0.5]

area

(8 cos (π x)), (8 x^{2} - 2), [- 0.5, 0.5]

6.42629 \dots

Solution steps

Apply the area formula:

\int_{- 0.5}^{0.5} 8 cos (π x) - (8 x^{2} - 2) d x

Solve

\int_{- 0.5}^{0.5} 8 cos (π x) - (8 x^{2} - 2) d x : 6.42629 \dots

The area is:

= 6.42629 \dots

\frac{\partial}{\partial y} ((x - 4) ln (x y))

θ \to 0 lim (sin (θ))

\frac{1}{2 r} + \frac{1}{8 r ^{\frac{7}{8}}}

\int_{0}^{l n (4)} \frac{e ^{x}}{e ^{2 x} + 25} d x

\frac{d}{d x} (ln (csc (x) - tan (x)))

What is area (8cos(pix)),(8x^2-2),[-0.5,0.5] ?
The answer to area (8cos(pix)),(8x^2-2),[-0.5,0.5] is 6.42629…