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Popular >

y^'-e^{6x+y}=0

Solution

y^{^{'}} - e^{6 x + y} = 0

Solution

y = - ln (- \frac{1}{6} e^{6 x} - c_{1})

Solution steps

y^{'} (x) - e^{6 x + y} = 0

Solve separable ODE:

y = - ln (- \frac{1}{6} e^{6 x} - c_{1})

y = - ln (- \frac{1}{6} e^{6 x} - c_{1})

Popular Examples

integral of x(x+1)^4

\int x (x + 1)^{4} d x

(arcsin (2 x))^{^{'}}

derivative of y=(arctan(3x))2 derivative of

y = (arctan (3 x)) 2

y^{''}-9y=e^{3x}

y^{^{''}} - 9 y = e^{3 x}

derivative of f(x)=x^{2/3}(x^2-4)derivative of

f (x) = x^{\frac{2}{3}} (x^{2} - 4)

Frequently Asked Questions (FAQ)

What is the solution for y^'-e^{6x+y}=0 ?
The solution for y^'-e^{6x+y}=0 is y=-ln(-1/6 e^{6x}-c_{1})