What is the derivative of {y}(θ,xtan(θ)) ?

The derivative of {y}(θ,xtan(θ)) is tan(θ) derivative of {y}(θ,x)

What is the first derivative of {y}(θ,xtan(θ)) ?

The first derivative of {y}(θ,xtan(θ)) is tan(θ) derivative of {y}(θ,x)

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\frac{d}{d x} (y (θ, x) tan (θ))

tan (θ) \frac{d}{d x} (y (θ, x))

Solution steps

\frac{d}{d x} (y (θ, x) tan (θ))

Treat

θ

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= tan (θ) \frac{d}{d x} (y (θ, x))

y \frac{d y}{d x} - y^{3} = y^{2} ln (x)

\frac{d}{d x} ((x - 2)^{2} + 2)

y^{^{'}} + 5 y = e^{- 3 t}

\frac{s + 2}{( s - 1 ) ( s + 3 ) ^{2}}

5 x - x^{2}

What is the derivative of {y}(θ,xtan(θ)) ?
The derivative of {y}(θ,xtan(θ)) is tan(θ) derivative of {y}(θ,x)
What is the first derivative of {y}(θ,xtan(θ)) ?
The first derivative of {y}(θ,xtan(θ)) is tan(θ) derivative of {y}(θ,x)