What is (\partial)/(\partial y)(4x^3-5x^2+8x) ?

The answer to (\partial)/(\partial y)(4x^3-5x^2+8x) is 0

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(\partial)/(\partial y)(4x^3-5x^2+8x)

\frac{\partial}{\partial y} (4 x^{3} - 5 x^{2} + 8 x)

0

Solution steps

\frac{\partial}{\partial y} (4 x^{3} - 5 x^{2} + 8 x)

Treat

x

as a constant

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

(e^{- x} sin (x))^{^{'}}

\int 4 x cos (x) d x

\int_{- 2}^{3} \frac{3}{x ^{4}} d x

\frac{\partial}{\partial x} (v)

n = 0 \sum \infty (- 1)^{n} x^{3 n}

What is (\partial)/(\partial y)(4x^3-5x^2+8x) ?
The answer to (\partial)/(\partial y)(4x^3-5x^2+8x) is 0