What is the derivative of e^{x^4+7x} ?

The derivative of e^{x^4+7x} is e^{x^4+7x}(4x^3+7)

What is the first derivative of e^{x^4+7x} ?

The first derivative of e^{x^4+7x} is e^{x^4+7x}(4x^3+7)

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\frac{d}{d x} (e^{x^{4} + 7 x})

e^{x^{4} + 7 x} (4 x^{3} + 7)

Solution steps

\frac{d}{d x} (e^{x^{4} + 7 x})

Apply the chain rule:

e^{x^{4} + 7 x} \frac{d}{d x} (x^{4} + 7 x)

= e^{x^{4} + 7 x} \frac{d}{d x} (x^{4} + 7 x)

\frac{d}{d x} (x^{4} + 7 x) = 4 x^{3} + 7

= e^{x^{4} + 7 x} (4 x^{3} + 7)

\frac{\partial}{\partial x} (7 + x ln (x y - 9))

\frac{d}{d x} ((x^{3} + 5 x^{2} - x^{- 2} + 8)^{- \frac{7}{6}})

q \to 0 + lim (4 q)

\int 22 x^{21} d x

x \to 8 lim (x^{\frac{8}{3}})

What is the derivative of e^{x^4+7x} ?
The derivative of e^{x^4+7x} is e^{x^4+7x}(4x^3+7)
What is the first derivative of e^{x^4+7x} ?
The first derivative of e^{x^4+7x} is e^{x^4+7x}(4x^3+7)