What is the d/(dt)((sin(t)+cos(t))^2) ?

The d/(dt)((sin(t)+cos(t))^2) is 2cos(2t)

What is the first d/(dt)((sin(t)+cos(t))^2) ?

The first d/(dt)((sin(t)+cos(t))^2) is 2cos(2t)

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\frac{d}{d t} ((sin (t) + cos (t))^{2})

2 cos (2 t)

Solution steps

\frac{d}{d t} ((sin (t) + cos (t))^{2})

Simplify

(sin (t) + cos (t))^{2} : 1 + sin (2 t)

= \frac{d}{d t} (1 + sin (2 t))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (1) + \frac{d}{d t} (sin (2 t))

\frac{d}{d t} (1) = 0

\frac{d}{d t} (sin (2 t)) = cos (2 t) \cdot 2

= 0 + cos (2 t) \cdot 2

Simplify

= 2 cos (2 t)

y = 5 x^{2} + \frac{6}{x}

y = \frac{8 t}{8 + t}

x \to 2 lim (2 x e^{x^{2}})

\int 2 x^{3} (1 - x^{4})^{- \frac{1}{4}} d x

\int \frac{x}{9 - 4 x ^{2}} d x

What is the d/(dt)((sin(t)+cos(t))^2) ?
The d/(dt)((sin(t)+cos(t))^2) is 2cos(2t)
What is the first d/(dt)((sin(t)+cos(t))^2) ?
The first d/(dt)((sin(t)+cos(t))^2) is 2cos(2t)