What is the derivative of 7x^{-1} ?

The derivative of 7x^{-1} is -7/(x^2)

What is the first derivative of 7x^{-1} ?

The first derivative of 7x^{-1} is -7/(x^2)

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\frac{d}{d x} (7 x^{- 1})

- \frac{7}{x ^{2}}

Solution steps

\frac{d}{d x} (7 x^{- 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 7 \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 7 (- 1 \cdot x^{- 1 - 1})

Simplify

7 (- 1 \cdot x^{- 1 - 1}) : - \frac{7}{x ^{2}}

= - \frac{7}{x ^{2}}

\int 2 x sin (3 x y) d x

x \to - 4 lim (x^{3} + x^{2})

\int_{2}^{5} f (x) d x

x \to \infty lim (- (\frac{1}{x}))

What is the derivative of 7x^{-1} ?
The derivative of 7x^{-1} is -7/(x^2)
What is the first derivative of 7x^{-1} ?
The first derivative of 7x^{-1} is -7/(x^2)