What is the derivative of 7/2 x^2-5x+1 ?

The derivative of 7/2 x^2-5x+1 is 7x-5

What is the first derivative of 7/2 x^2-5x+1 ?

The first derivative of 7/2 x^2-5x+1 is 7x-5

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\frac{d}{d x} (\frac{7}{2} x^{2} - 5 x + 1)

7 x - 5

Solution steps

\frac{d}{d x} (\frac{7}{2} x^{2} - 5 x + 1)

Simplify

\frac{7}{2} x^{2} - 5 x + 1 : \frac{7 x ^{2}}{2} - 5 x + 1

= \frac{d}{d x} (\frac{7 x ^{2}}{2} - 5 x + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{7 x ^{2}}{2}) - \frac{d}{d x} (5 x) + \frac{d}{d x} (1)

\frac{d}{d x} (\frac{7 x ^{2}}{2}) = 7 x

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (1) = 0

= 7 x - 5 + 0

Simplify

= 7 x - 5

\frac{\partial}{\partial x} (cos^{2} (y))

y = \frac{x ^{2} - 1}{x ^{2} + x + 1}

\frac{d}{d x} (s e^{s x})

y^{^{'}} = y + y^{3}

What is the derivative of 7/2 x^2-5x+1 ?
The derivative of 7/2 x^2-5x+1 is 7x-5
What is the first derivative of 7/2 x^2-5x+1 ?
The first derivative of 7/2 x^2-5x+1 is 7x-5