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Popular >

derivative of (e^{2x}+e^{4x}/3)

Solution

\frac{d}{d x} (\frac{e ^{2 x} + e ^{4 x}}{3})

Solution

\frac{1}{3} (e^{2 x} \cdot 2 + e^{4 x} \cdot 4)

Solution steps

\frac{d}{d x} (\frac{e ^{2 x} + e ^{4 x}}{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{3} \frac{d}{d x} (e^{2 x} + e^{4 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{1}{3} (\frac{d}{d x} (e^{2 x}) + \frac{d}{d x} (e^{4 x}))

\frac{d}{d x} (e^{2 x}) = e^{2 x} \cdot 2

\frac{d}{d x} (e^{4 x}) = e^{4 x} \cdot 4

= \frac{1}{3} (e^{2 x} \cdot 2 + e^{4 x} \cdot 4)

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x \to 4 lim (\frac{x + 1}{x - 3})

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\int (x^{2} - 3 x) d x

(\partial)/(\partial x)(e^{x^2+y^2})

\frac{\partial}{\partial x} (e^{x^{2} + y^{2}})

integral from 0 to 2 of 2/(sqrt(8-x^2))

\int_{0}^{2} \frac{2}{8 - x ^{2}} d x

Frequently Asked Questions (FAQ)

What is the derivative of (e^{2x}+e^{4x}/3) ?
The derivative of (e^{2x}+e^{4x}/3) is 1/3 (e^{2x}*2+e^{4x}*4)
What is the first derivative of (e^{2x}+e^{4x}/3) ?
The first derivative of (e^{2x}+e^{4x}/3) is 1/3 (e^{2x}*2+e^{4x}*4)