What is the solution for x'=0.0333333x(30-x) ?

The solution for x'=0.0333333x(30-x) is x=(0.999999)/(-e^{\frac{-c_{1)-t}{1.000001}}+0.0333333}

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x'=0.0333333x(30-x)

x^{^{'}} = 0.0333333 x (30 - x)

x = \frac{0.999999}{- e ^{\frac{- c _{1} - t}{1.000001}} + 0.0333333}

Solution steps

x^{'} (t) = 0.0333333 x (30 - x)

Solve Bernoulli ODE:

x = \frac{0.999999}{- e ^{\frac{- c _{1} - t}{1.000001}} + 0.0333333}

x = \frac{0.999999}{- e ^{\frac{- c _{1} - t}{1.000001}} + 0.0333333}

x \to 2 lim (\frac{x ^{3} - 3 x ^{2} + 4}{3 x ^{3} - 18 x ^{2} + 36 x - 24})

\int_{4}^{\infty} 9 e^{- \frac{y}{2}} d y

k = 1 \sum \infty \frac{3 k ^{8}}{k !}

\frac{\partial}{\partial x} (ln (x y^{4}))

y = 3 x e^{2 x}

What is the solution for x'=0.0333333x(30-x) ?
The solution for x'=0.0333333x(30-x) is x=(0.999999)/(-e^{\frac{-c_{1)-t}{1.000001}}+0.0333333}