What is (\partial)/(\partial t)(40y+z+10t) ?

The answer to (\partial)/(\partial t)(40y+z+10t) is 10

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(\partial)/(\partial t)(40y+z+10t)

\frac{\partial}{\partial t} (40 y + z + 10 t)

10

Solution steps

\frac{\partial}{\partial t} (40 y + z + 10 t)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial t} (40 y) + \frac{\partial}{\partial t} (z) + \frac{\partial}{\partial t} (10 t)

\frac{\partial}{\partial t} (40 y) = 0

\frac{\partial}{\partial t} (z) = 0

\frac{\partial}{\partial t} (10 t) = 10

= 0 + 0 + 10

Simplify

= 10

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What is (\partial)/(\partial t)(40y+z+10t) ?
The answer to (\partial)/(\partial t)(40y+z+10t) is 10