What is the slope of y= 1/(x-1) ?

The slope of y= 1/(x-1) is -1/((x-1)^2)

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slope of y= 1/(x-1)

slope

y = \frac{1}{x - 1}

- \frac{1}{( x - 1 ) ^{2}}

Solution steps

y = \frac{1}{x - 1}

In order to find the slope of the function, take the derivative of

\frac{1}{x - 1}

\frac{d}{d x} (\frac{1}{x - 1}) = - \frac{1}{( x - 1 ) ^{2}}

- \frac{1}{( x - 1 ) ^{2}}

x \to - 1 lim (x ∣ x - 4 ∣)

\frac{d}{d x} ((arcsin (x))^{2})

\int \frac{t ^{2}}{2 1 - t ^{2}} d t

t^{2} y^{^{'}} + 4 t y - y^{3} = 0, y (1) = \frac{3}{2}

f (x) = x 2^{x}